Anyways, I want to talk to you about question 3 a): Write down the definition of a rational number. Most people answered this incorrectly, and here are some of the responses I received:
- Any number that is not a fraction.
- Any number which can be expressed as p/q where p,q ∈ ℝ and p ≤ q. 3
- A number that exists rationally.
- Any number that is not irrational.
- A number that makes scence(sic).
- Any number that doesn't believe in fairy tales4.
- Definition of a rational number. There is a chap in class who I always thought was an ace but he has written less than I. I guess I am not the only person who was either stumped by this course or who didn't work on it hard enough & is now compelled to write Ramayamas in the answer sheet. Yay! 15 minutes to go. Actually 20 mins but I think I am going to make a run for it. Have no clue what I am writing and I think am simply allowing all thoughts to spill out onto paper. Possibly my constant scribbling is leading the guy next to me to get very worried as he isn't writing anything either. I wish I could go home for a bit. Really wish I could go home if only it wasn't 18 hours away.
1Which may be safely characterised as being to world literature what a ham bone stew is to world cuisine. P.S. Fuck you, yes, this is a footnote. Despite your endless pay-outs on this front, I still like the fucking things.
2In New Zealand Universities 'courses' are called 'papers'. This caused some confusion for me when in casual conversation a great number of people started casually talking about papers they did in first year. I thought I was surrounded by geniuses. P.S. Yes, this is another footnote. Go to hell.
3I had to at least acknowledge internal consistency here. When asked to prove that √3 was irrational they said: √3 = 3/√3 and, since 3 > √3, √3 is irrational. The correct answers were kind of cute, too, actually (& not the way I've ever seen this answered). They reasoned as follows: Let p,q ∈ ℤ. Then the prime factorization of both p2 and q2 contain an even number of terms. Thus p2≠ 3q 2 and so √3 ≠ p/q.
4This guy got marks.
8 comments:
I like footnotes.
Poor number 7.
They're not being internally rigorous though. sqrt(3) = -3 / -sqrt(3), and -3 is less than -sqrt(3).
Yeah, but everybody knows that negative numbers are crazy, so.....
You mean that everyone knows negative numbers don't really exist, right Fitz?
That's right.
If you don't write another post soon, your penis will fall off.
Yes, I am aware of that.
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